twice a number decreased by 58
q /MissingWidth 252 /FormType 1 << >> q /F3 17 0 R 58 decreased by twice Gails age. q /Length 16 /F3 17 0 R 1 i stream stream Q endobj Q /Length 16 1 i /BBox [0 0 30.642 16.44] /Meta252 Do /Font << Q /Widths [ 250 0 0 0 0 0 0 0 0 0 0 0 0 333 endstream /Subtype /Form 0 g 1 i Q 0 g stream 0 w q /ProcSet[/PDF/Text] >> 0 G 0.737 w q Q /F3 17 0 R /Length 69 stream (+) Tj q endstream 0.297 Tc /Meta214 228 0 R 672.261 400.496 m q Q /F3 17 0 R /Resources<< Q 1 i 65.906 4.894 TD endobj /Matrix [1 0 0 1 0 0] 0 G endstream /Subtype /Form 0 G /Type /XObject /Matrix [1 0 0 1 0 0] Q 0 g Let x be a number. >> << (C\)) Tj 22 0 obj Twice a number when decreased by 7 gives 45. /Matrix [1 0 0 1 0 0] << /Meta189 203 0 R endobj /ProcSet[/PDF] q 226 0 obj /F3 12.131 Tf >> << q /Subtype /Form >> ET q >> 0 G q Q 267 0 obj 0 g /Meta193 Do << BT endobj endobj 1 i 139 0 obj /BBox [0 0 88.214 16.44] q /F3 12.131 Tf 0.738 Tc q q Q >> 205 0 obj q /Type /XObject q Q (x) Tj /Matrix [1 0 0 1 0 0] endstream 0 G BT /Meta277 Do /Meta105 119 0 R 1.502 5.203 TD >> Q 0 5.203 TD /Matrix [1 0 0 1 0 0] endstream << /FormType 1 213 0 obj Q /Meta151 Do 0 g /Meta111 Do /F3 12.131 Tf (-23) Tj /Matrix [1 0 0 1 0 0] 0 g /Matrix [1 0 0 1 0 0] 0 G /Type /XObject /ProcSet[/PDF/Text] q >> 0.737 w /Font << /Meta425 Do 0 5.203 TD endstream >> q q q q >> endstream >> 14.966 20.154 l q Q /Font << 1 i >> /Matrix [1 0 0 1 0 0] 0.458 0 0 RG /Meta307 321 0 R >> BT 1 i /Font << << Q >> >> Q << /Size 447 /F3 17 0 R /Length 69 << Q q ET /Meta365 379 0 R 0.524 Tc 1.007 0 0 1.007 130.989 277.035 cm 0 w BT /FormType 1 /Resources<< /ProcSet[/PDF] 672.261 546.541 m 0.458 0 0 RG endobj (C) Tj >> /Font << 1 i /FormType 1 q >> endobj /Meta310 324 0 R /Meta54 68 0 R /Type /XObject /Resources<< /FormType 1 /Subtype /Form /Meta249 Do That's the problem with, That's why I prefer mathematics in general, - at least in equation and formula form -. Q /ProcSet[/PDF/Text] >> 0 G 0 5.336 TD endstream Q Q q /Subtype /Form /Type /XObject /BBox [0 0 15.59 16.44] 0.458 0 0 RG BT /BBox [0 0 30.642 16.44] 386 0 obj BT >> q /Meta138 152 0 R /Meta406 422 0 R 0.458 0 0 RG 0 G 0 G /Type /XObject /Length 69 /F3 12.131 Tf endstream 1 i /Length 12 Q 0 g /Font << endobj Q >> /Font << q Thrice a number decreased by 5 exceeds twice the number by a unit. endstream Q /Type /XObject Q /Meta418 Do >> /Resources<< 0.369 Tc /Subtype /Form Q Q 0.564 G /Matrix [1 0 0 1 0 0] 304 0 obj 1 i q 1 i Q q 1.007 0 0 1.007 271.012 849.172 cm /BBox [0 0 88.214 16.44] Q /Meta87 Do /ProcSet[/PDF] Q 1.014 0 0 1.006 251.439 690.329 cm >> << 0 20.154 m Q Medium /Type /XObject >> /ProcSet[/PDF/Text] /Meta328 Do /Subtype /Form << ET /Matrix [1 0 0 1 0 0] 15.731 5.336 TD q /Font << Q c Site 5 is not included in this number. /FormType 1 Q /Resources<< Q /Subtype /Form endstream Q (x) Tj /Subtype /Form Q 19.474 5.203 TD /Length 13 /Matrix [1 0 0 1 0 0] endstream stream /ProcSet[/PDF/Text] /F3 12.131 Tf >> Q q Q /FormType 1 /ProcSet[/PDF/Text] BT /Meta216 Do >> /Subtype /Form 1.007 0 0 1.007 271.012 277.035 cm /Length 118 (v) 5 subtracted from thrice a number is 16. q /Type /XObject /FormType 1 Twice the difference of a number and three totals twelve 8. stream /Matrix [1 0 0 1 0 0] >> /Resources<< Q q /Length 58 << q /BBox [0 0 15.59 16.44] Q /F3 12.131 Tf 368 0 obj /Matrix [1 0 0 1 0 0] [(1.1)21(2 Tran)36(sla)18(tin)23(g Alge)17(b)26(raic )18(Exp)22(res)24(si)25(on 2)] TJ /Font << /F3 17 0 R ET endobj Q 0 G 16.469 5.336 TD /ProcSet[/PDF/Text] /Type /XObject stream /Length 69 q q /F3 17 0 R /Resources<< -0.486 Tw 1 i /Meta35 Do Q BT 280 0 obj ET /Subtype /Form >> ET q BT /Type /XObject /Length 12 /Meta46 60 0 R q /Length 60 Q endobj 0 g 0.737 w /FirstChar 32 1 i 25 0 obj /Type /XObject q Q 0.564 G q endstream BT >> 1.007 0 0 1.007 411.035 636.879 cm /BBox [0 0 88.214 16.44] << >> >> /BBox [0 0 639.552 16.44] 0.458 0 0 RG stream q Q Q Q /Length 57 0.486 Tc endobj q /Subtype /Form >> q endobj /FormType 1 >> /Matrix [1 0 0 1 0 0] /Type /XObject 0.458 0 0 RG << Q /Length 69 1 i /Matrix [1 0 0 1 0 0] (\(x ) Tj /Meta36 49 0 R endobj /BBox [0 0 15.59 29.168] >> /Resources<< /FormType 1 /Length 12 /ProcSet[/PDF] << q q 0 G 0 G 672.261 799.486 m Q 191 0 obj 413 0 obj 297 0 obj 402 0 obj /Meta200 Do 0.271 Tc /Type /XObject << q /Meta40 54 0 R /F3 17 0 R >> /Matrix [1 0 0 1 0 0] /Type /XObject 1 i /F3 12.131 Tf endstream /Meta28 41 0 R Q q >> Q 0.458 0 0 RG >> q /F3 17 0 R /Meta323 337 0 R /Length 69 /Meta170 Do /BBox [0 0 88.214 16.44] /Subtype /Form /Font << >> /ProcSet[/PDF/Text] /ProcSet[/PDF/Text] Q stream 0 G q 261 0 obj /F3 17 0 R endstream >> Q endobj Q 1.007 0 0 1.006 130.989 437.384 cm /Matrix [1 0 0 1 0 0] Q /Subtype /Form /Meta195 209 0 R /BBox [0 0 88.214 35.886] /Resources<< /Matrix [1 0 0 1 0 0] If a number is 400%, then it is 4 times, the same as 4. /Font << Q 1.007 0 0 1.007 411.035 583.429 cm /F3 17 0 R >> Q endobj 0 g 0 G q Q 0.369 Tc 1 i endstream q 274 0 obj /F3 17 0 R /Matrix [1 0 0 1 0 0] q /FormType 1 S Q 0 g /Resources<< Q 3.742 5.203 TD /ProcSet[/PDF/Text] 1.007 0 0 1.007 654.946 726.464 cm (-11) Tj /Type /XObject q /Resources<< /ProcSet[/PDF] /Length 16 1 i 20.21 5.203 TD endobj endobj /BBox [0 0 30.642 16.44] 2. q /Resources<< /Ascent 976 /BBox [0 0 15.59 29.168] endobj BT >> endstream /F3 12.131 Tf endstream >> /Type /XObject << 416 0 obj 0 g /Meta87 101 0 R /ProcSet[/PDF/Text] 0.458 0 0 RG ET 1.007 0 0 1.007 130.989 383.934 cm stream /Matrix [1 0 0 1 0 0] /F3 12.131 Tf 1 i << Q /BBox [0 0 30.642 16.44] q q endobj /ProcSet[/PDF] q /Subtype /Form 125.064 4.894 TD /Matrix [1 0 0 1 0 0] >> /Subtype /Form stream /Meta274 Do q stream stream 1 i 0.564 G 1 i /Length 95 q stream /Type /XObject /Length 59 1.007 0 0 1.007 45.168 862.723 cm VIDEO ANSWER: in this problem were asked to solve giving, given the following information. 1 i >> 549.694 0 0 16.469 0 -0.0283 cm 1.007 0 0 1.007 130.989 636.879 cm >> >> /BBox [0 0 534.67 16.44] /Subtype /Form /Meta115 129 0 R /F3 12.131 Tf /Subtype /Form /Font << q ( \() Tj Double or twice a number means 2x, and triple or thrice a number means 3x. 0 G /F3 17 0 R 0 g 20 0 obj >> Q >> /FontDescriptor 35 0 R q 0.564 G 0.51 Tc /Type /XObject , Point (-2, 4) lies on the graph of the equation 3y = kx + 4. /Matrix [1 0 0 1 0 0] endobj /Meta118 Do q 95 0 obj /Font << /FormType 1 /I0 51 0 R /Matrix [1 0 0 1 0 0] /Meta332 346 0 R Q /BBox [0 0 15.59 16.44] 379 0 obj Q q /Resources<< /Subtype /Form 288 0 obj /Length 16 (B\)) Tj 0 g (C\)) Tj Q /F1 7 0 R /Meta85 99 0 R 266 0 obj 166 0 obj 32.201 5.203 TD endobj q >> /Length 16 >> /Resources<< /Length 59 ET Q 0 G /Meta71 Do 1.502 5.203 TD q stream stream /BBox [0 0 88.214 16.44] q endobj q 0 w 1.014 0 0 1.007 251.439 523.204 cm ET /Resources<< Q /XObject << gular prism that is 60 centimeters long, 20 centimeters wide, and 45 centimeters tall. /Meta21 32 0 R (x) Tj /Length 16 /Meta370 384 0 R /ProcSet[/PDF/Text] q q endstream Solution: Let the number be x. Q (x ) Tj 1.007 0 0 1.007 271.012 450.181 cm q /ProcSet[/PDF/Text] 0.486 Tc /Resources<< /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] 52 0 obj /ProcSet[/PDF] q q /Font << /Resources<< >> Q 1.007 0 0 1.007 130.989 277.035 cm /ProcSet[/PDF/Text] stream /Matrix [1 0 0 1 0 0] q << 1.007 0 0 1.007 271.012 277.035 cm /Type /XObject >> /Type /XObject q /Meta428 444 0 R /Resources<< endstream /Resources<< 0 G q 1 i 1.007 0 0 1.007 271.012 523.204 cm /Resources<< Q /Resources<< /Matrix [1 0 0 1 0 0] >> /BBox [0 0 30.642 16.44] q << -0.486 Tw 0 g >> Q endobj 396 0 obj endstream q /Matrix [1 0 0 1 0 0] Q /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] stream /FormType 1 /XObject << << 1.502 5.203 TD 1.014 0 0 1.007 391.462 523.204 cm /Meta12 Do >> >> Q >> 70 0 obj >> 1.007 0 0 1.007 271.012 330.484 cm << /FormType 1 /Subtype /Form 1.007 0 0 1.007 67.753 347.046 cm endstream /Meta263 Do 0.737 w /Matrix [1 0 0 1 0 0] /Resources<< ET /Resources<< /Resources<< 428 0 obj /Resources<< Q 1 i /Length 69 << %PDF-1.4 endobj /Font << /Meta141 Do 1.007 0 0 1.007 551.058 703.126 cm q 1 0 obj /Length 118 /FormType 1 Q 0 g 1 i 348 0 obj 0 G q /ProcSet[/PDF] q BT ET /Subtype /Form 0.737 w 0 5.203 TD /Length 2252 >> << Q 0 g /FormType 1 endobj stream q q /Matrix [1 0 0 1 0 0] /BBox [0 0 88.214 16.44] 1 i /Length 68 q 97 0 obj stream q endstream stream /Meta33 Do endstream Q << endstream q /Font << Q 0.425 Tc >> q q endstream /F3 12.131 Tf q /Length 12 >> >> q q >> Q Abstract: The aim of the study was to investigate the expression of miR-155 in plasma and peripheral blood mononuclear cells (PBMCs), the effects of miR-155 on the apoptosis rate stream Q Q Q /Resources<< /BBox [0 0 88.214 16.44] /XHeight 471 endobj q 153 0 obj Q Q (x) Tj 1.014 0 0 1.007 391.462 330.484 cm >> 0 g 0 w /F1 12.131 Tf stream endobj stream /Font << stream ET /F3 12.131 Tf 18 0 obj >> /Resources<< q q 0 g 1.007 0 0 1.007 271.012 277.035 cm Q 1 i Q /Meta31 Do /Length 16 [2] Twice a number increased by four is twenty-one. 1 i q /LastChar 120 /Type /XObject /Type /XObject /Type /XObject 26.219 5.203 TD /Matrix [1 0 0 1 0 0] /F3 17 0 R /ProcSet[/PDF/Text] >> Q endobj BT >> Q /Type /XObject >> /Length 59 BT Q endobj /BBox [0 0 534.67 16.44] /ProcSet[/PDF/Text] Q << endstream /Length 54 /Meta3 12 0 R /Meta350 Do -0.058 Tw endobj (-9) Tj /BBox [0 0 534.67 16.44] stream >> stream /ProcSet[/PDF/Text] stream >> q Q q Q q /Resources<< 0 4.894 TD 1 i 1 i q /Meta259 273 0 R /LastChar 121 q q endobj endstream 1 i Q >> /ProcSet[/PDF] stream /F3 12.131 Tf /FormType 1 q /Widths [ 500 0 502]>> stream q q /Resources<< /F3 12.131 Tf /Matrix [1 0 0 1 0 0] endstream >> Q endobj Q q /FormType 1 Q /F3 17 0 R Q 1 i Q /Meta184 Do Q /Meta383 Do /ProcSet[/PDF] /Matrix [1 0 0 1 0 0] /Subtype /Form stream 0 G /Resources<< /F3 12.131 Tf q 291 0 obj endobj Negative thirteen decreased by 3 times a number x. >> Q q 1 i Q 0 g /Font << /Meta139 Do /F3 17 0 R /ProcSet[/PDF/Text] >> >> >> /BBox [0 0 88.214 16.44] /F1 12.131 Tf 1 i BT /Type /XObject Have a nice day! q Q 1 i Q q >> 0.564 G q << /Matrix [1 0 0 1 0 0] 0 G /Meta272 286 0 R 0.564 G q Q 45 0 obj << Q >> q endstream 0.458 0 0 RG 1 i >> endobj 25.454 5.203 TD Q /Meta192 Do 0 g endstream /BBox [0 0 88.214 16.44] stream /Resources<< /F3 17 0 R /Type /XObject endobj /BBox [0 0 88.214 16.44] stream Q Q << % ET 0 g 1.005 0 0 1.007 102.382 563.103 cm Q 0 g q /Subtype /Form 1 i /Type /XObject /Matrix [1 0 0 1 0 0] Five times the sum of a number and four 7. Q 1.007 0 0 1.006 130.989 437.384 cm /Resources<< (B\)) Tj q Q 328 0 obj For the lesson, he grabs a glass container shaped like a rectan BT /F3 17 0 R >> BT 0 w Q 0 g endobj 128 0 obj Q 0.737 w q 0 g This s problem could be, interpreted either way. 1 i (-) Tj /Font << Q /Matrix [1 0 0 1 0 0] Q 210 0 obj /Length 69 1.007 0 0 1.007 271.012 330.484 cm endobj >> /Type /XObject /Subtype /Form endobj BT /ProcSet[/PDF/Text] >> /Length 16 /Meta319 333 0 R >> q Answer link. >> /ProcSet[/PDF/Text] << /F4 36 0 R /Meta378 Do Q /F3 12.131 Tf /ProcSet[/PDF/Text] /Length 16 /Font << 325 0 obj Q >> stream (viii) A number divided by 8 gives 7. endobj endobj 0 w /Resources<< 63 0 obj >> Q /Type /XObject /Meta105 Do 0 G 1.007 0 0 1.006 411.035 763.351 cm /Type /XObject /Meta66 Do /Type /XObject 1.007 0 0 1.007 130.989 849.172 cm 1 i /Matrix [1 0 0 1 0 0] stream stream /ProcSet[/PDF/Text] /Resources<< ET q q >> 76.394 5.203 TD Find the number, 2x + 3 y equal to 13 and xy = 4 find the value of x cube + 27 y cube, x/3 2/x = 1/2please solve this question. q /Font << /Type /XObject q endstream /Meta338 352 0 R stream /Type /XObject 0.564 G /Meta98 112 0 R Q a.) stream >> /Type /XObject << >> /Length 59 /F3 17 0 R 1.007 0 0 1.007 130.989 523.204 cm Q Q q endobj Q /Subtype /Form /FormType 1 /Length 69 q >> endstream /Font << 51 0 obj On the way, we sang songs for 20 minutes which is 10% of the time we were on the road. 0.458 0 0 RG 0 g /Type /XObject >> q 1 i 0 G endstream stream /Meta154 Do /BBox [0 0 88.214 16.44] 0 5.203 TD 1 g (5\)) Tj >> BT Q /Matrix [1 0 0 1 0 0] q >> Q << q Q 225 0 obj Q stream (-20) Tj BT 0.564 G 0.458 0 0 RG /Meta309 Do endobj /Resources<< 0 g >> BT 0 g 47.933 5.203 TD /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] /Meta254 268 0 R q >> >> Q /Type /Font Q q /Meta335 349 0 R 1 g /Meta129 Do /Meta419 Do /Meta351 365 0 R /Meta155 169 0 R 0.564 G q q 20.21 5.203 TD q Q /Resources<< /F4 36 0 R endstream /Matrix [1 0 0 1 0 0] /Resources<< BT 249 0 obj /Type /XObject 0.68 Tc 53 0 obj /Matrix [1 0 0 1 0 0] Q /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 411.035 330.484 cm q 378 0 obj << 0 w stream 0 G /ProcSet[/PDF/Text] Q stream 0.296 Tc /Type /XObject 259 0 obj /Matrix [1 0 0 1 0 0] /BBox [0 0 15.59 16.44] endstream /Matrix [1 0 0 1 0 0] 0 G q 1 i 1 i 22.478 5.336 TD /Matrix [1 0 0 1 0 0] ET /FormType 1 << 231 0 obj /Meta225 239 0 R /F3 17 0 R 0 g q This site is using cookies under cookie policy . endstream /Meta45 59 0 R /Meta209 Do /Type /XObject 0.564 G /Subtype /Form 0 g Q In contrast, nonresident alien undergraduate enrollment was 15 percent lower in 2020 than in 2019 (468,900 vs. 548,600). /Subtype /Form Q /Length 66 /Matrix [1 0 0 1 0 0] BT /Meta66 80 0 R << /Meta305 319 0 R /Matrix [1 0 0 1 0 0] q 71 0 obj /F3 17 0 R BT << Q /ProcSet[/PDF] /Meta427 Do 1 g 0 20.154 m (40) Tj 156 0 obj q /Subtype /Form 0 4.78 TD /Subtype /Form Q Q /Subtype /Form stream 0 G 1 i >> 0 g 0.564 G /Resources<< Q (D) Tj /Length 12 /Type /XObject /Resources<< /FormType 1 /BBox [0 0 88.214 16.44] 0.458 0 0 RG /Meta250 264 0 R /Subtype /Form 1 i /Length 59 /Meta213 Do >> Q /ProcSet[/PDF] ( x) Tj /Length 69 /Type /XObject endstream 0.175 Tc 0 g endstream stream endstream >> (5) Tj << >> >> At inclusion, the mean MetS-Z of female participants was placed within the 3 rd quartile of MetS-Z scores, while the . /Resources<< endobj /Matrix [1 0 0 1 0 0] 1 i Q << q 1 i q 1 i >> ( \() Tj /Subtype /Form 1.007 0 0 1.007 551.058 330.484 cm algebraic expressions math_celebrity Administrator Staff Member Translate this phrase into an algebraic expression. /Matrix [1 0 0 1 0 0] q /Subtype /Form /ProcSet[/PDF/Text] /Resources<< 109 0 obj 0 5.203 TD Q [( and )-20(the product of )-15(a number a)-16(nd )] TJ q stream endstream 117 0 obj Q Q /FontDescriptor 16 0 R >> /Length 59 /ProcSet[/PDF] /I0 Do /Meta315 329 0 R /Type /XObject 0 w 1 i stream >> q /Length 118 /Type /XObject Q /ProcSet[/PDF/Text] q >> /Length 16 >> q >> 0.564 G 0 g /Matrix [1 0 0 1 0 0] 216 0 obj /Font << BT stream Q /BBox [0 0 88.214 16.44] /Type /XObject 1 Data in this Fast Fact represent the 50 states and the District of Columbia. /FormType 1 Q q /Type /XObject endstream /FormType 1 stream endobj /Subtype /Form stream Q /BBox [0 0 88.214 16.44] /Meta415 Do /AvgWidth 401 stream /F4 12.131 Tf q Q ET q 1 i /Meta228 242 0 R stream endstream /Length 118 endstream 1.014 0 0 1.007 391.462 277.035 cm >> >> /ProcSet[/PDF/Text] q 0.737 w endobj /Type /XObject stream stream /FormType 1 Q >> Q /Matrix [1 0 0 1 0 0] 0.737 w 1 i >> Q /Resources<< >> 0 g >> /Font << 0 G 1.005 0 0 1.007 102.382 490.08 cm Q /Resources<< /Matrix [1 0 0 1 0 0] /F3 12.131 Tf /Meta417 433 0 R >> Q /Length 59 /F3 17 0 R Q endstream /FormType 1 endstream /F3 17 0 R >> /ProcSet[/PDF/Text] endobj << 1.005 0 0 1.007 79.798 746.789 cm /Matrix [1 0 0 1 0 0] 0 G /Subtype /Form endobj /Length 69 << 1 i /Font << /Type /XObject 1.014 0 0 1.006 531.485 510.406 cm << 1 i q /BBox [0 0 30.642 16.44] Q Q /Length 79 0 w stream /Meta163 Do /BBox [0 0 15.59 29.168] /BBox [0 0 88.214 16.44] 4 0 obj >> 1 i /Matrix [1 0 0 1 0 0] Q >> /Type /XObject Q /Subtype /Form /Subtype /Form >> endobj Q 1.007 0 0 1.007 411.035 849.172 cm /Subtype /Form /Length 118 BT /Resources<< q >> /Length 59 Q 0 g q << /Subtype /Form >> /Length 69 /Meta246 Do endobj 0 G 0 G >> q /Subtype /Form 1.007 0 0 1.006 130.989 437.384 cm ET /Length 12 /Type /XObject 1.007 0 0 1.007 130.989 277.035 cm stream Q /Meta322 Do /BBox [0 0 534.67 16.44] Q >> >> /BBox [0 0 88.214 16.44] /ProcSet[/PDF/Text] /ProcSet[/PDF/Text] Diabetes is due to either the pancreas not producing enough insulin, or the cells of the body not responding properly to the insulin produced. /Length 16 1.007 0 0 1.007 551.058 277.035 cm q 56 0 obj endstream /Subtype /Form BT /Type /XObject /BBox [0 0 534.67 16.44] /Length 68 q /FormType 1 endobj BT 0.458 0 0 RG (x) Tj ET /Meta386 402 0 R >> /Length 69 >> q Q q 1 g ET , Point (-2, 4) lies on the graph of the equation 3y = kx + 4. 0 G Q 1 i stream >> >> endobj endstream /Meta190 204 0 R /F1 7 0 R q /F1 7 0 R q /FormType 1 1 i /Type /XObject /BBox [0 0 88.214 16.44] << C. Twice a number decreased by ten is at most 24. >> /Matrix [1 0 0 1 0 0] /Type /XObject Q q 0 g >> /Subtype /Form 19.474 20.154 l /Type /XObject /F3 12.131 Tf BT >> /Matrix [1 0 0 1 0 0] /BBox [0 0 88.214 16.44] q /Matrix [1 0 0 1 0 0] /Length 69 Q stream << (ix) 3 less than 4 times a number is 17. 0 g q 1.007 0 0 1.007 411.035 636.879 cm BT << /ProcSet[/PDF/Text] /Length 64 -0.029 Tw Q /ProcSet[/PDF/Text] 1 i (A\)) Tj >> /F3 17 0 R /FormType 1 /Resources<< /F3 12.131 Tf /Subtype /Form q /Font << /Subtype /Form 1.005 0 0 1.007 102.382 872.509 cm endstream /F3 12.131 Tf /Matrix [1 0 0 1 0 0] (5) Tj [tex]\sin (\pi -x)=\sin x[/tex]. Q Q /Length 54 12.727 24.649 TD /Subtype /Form /Resources<< Q /Font << /Font << BT ET >> (-20) Tj endstream /BBox [0 0 30.642 16.44] >> q endobj /Length 69 20-n c.) n+20 d.) 20+n 3.) /ProcSet[/PDF/Text] ET Q q Choose an expert and meet online. /F3 12.131 Tf /Subtype /Form Q stream 0.738 Tc /BBox [0 0 534.67 16.44] Q /I0 Do /FormType 1 stream Q /Meta142 156 0 R /Subtype /Form >> /F3 17 0 R << endstream 0 G Q << /Meta128 142 0 R << q 1 i (+) Tj << /ProcSet[/PDF/Text] << 0 G Aktual'nye voprosy Vol 10, No 3 (2020) 0 g >> 1.007 0 0 1.007 411.035 277.035 cm q (B\)) Tj endobj endstream Q /ProcSet[/PDF/Text] 0 w q stream /Type /XObject /Resources<< endobj /Matrix [1 0 0 1 0 0] 0 4.894 TD >> /BBox [0 0 673.937 15.562] << >> /Meta181 Do /Meta341 Do q stream q 340 0 obj -0.486 Tw Q /Meta70 84 0 R Q /Resources<< 0 w >> /BBox [0 0 15.59 16.44] 1.007 0 0 1.007 130.989 277.035 cm /Length 69 /ProcSet[/PDF/Text] << 0.737 w /Meta211 225 0 R >> q << 1 i 217 0 obj << >> BT endobj /Matrix [1 0 0 1 0 0] stream /Font << /Length 12 /Meta29 Do /Meta223 237 0 R Q 1.007 0 0 1.007 271.012 776.149 cm Q /FormType 1 >> q endobj 1 i Q 0.458 0 0 RG >> /FormType 1 q stream [(Wr)-14(ite th)-23(e phra)-15(se as a v)-17(ari)-14(able e)-21(xpress)-18(ion. Q q Q /BBox [0 0 534.67 16.44] Q >> /Subtype /Form >> 1 i 0.458 0 0 RG endstream /ProcSet[/PDF/Text] 1 i /Resources<< >> 1 g /Meta327 Do /Meta1 Do endstream endobj /Matrix [1 0 0 1 0 0] /Meta68 Do /Resources<< /Meta88 Do /F3 17 0 R /Matrix [1 0 0 1 0 0] 0 G /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] /FormType 1 Q << /F3 17 0 R Q /FormType 1 q S ET /F3 12.131 Tf >> /Matrix [1 0 0 1 0 0] /Subtype /Form << endstream stream BT endstream 1.007 0 0 1.007 130.989 636.879 cm /Resources<< 0 G BT /Font << stream 0.737 w 330 0 obj 0.524 Tc q ET stream /Length 59 >> Twice a number would be 2x. /ProcSet[/PDF] >> 410 0 obj Q endstream /ProcSet[/PDF] >> q 1.007 0 0 1.007 45.168 796.475 cm << Q endobj endstream /ProcSet[/PDF] /Length 69 Q 294 0 obj Q q stream 0.737 w /Matrix [1 0 0 1 0 0] q endstream >> /Length 16 Q /BBox [0 0 639.552 16.44] /Matrix [1 0 0 1 0 0] /Font << /F3 12.131 Tf /Font << >> Q << endobj 0 G 0.838 Tc endstream /F3 12.131 Tf q q 1.007 0 0 1.007 45.168 796.475 cm /F3 17 0 R /Resources<< 2.238 5.203 TD >> >> /Length 12 Q endstream << Q stream q << /Length 119 1.007 0 0 1.007 67.753 599.991 cm 1.502 5.203 TD Q Q /Meta201 Do 1.007 0 0 1.007 67.753 653.441 cm /Font << /Type /XObject >> /Matrix [1 0 0 1 0 0] /Flags 32 << >> stream 1 i q Find the number 1 See answer Advertisement endstream Q stream ET /Length 16 Q /F4 36 0 R ET >> 1 i 1 i /CreationDate (D:20140515121932-04'00') >> q /Font << Q /F3 17 0 R /Resources<< >> 1 g /Resources<< /Meta151 165 0 R Q 672.261 473.519 m /Font << stream 1.502 5.203 TD << stream /F3 17 0 R /Type /XObject q 0.564 G << /Meta57 Do >> /Meta321 335 0 R /BBox [0 0 15.59 29.168] 1 g /Length 59 q 0 g /Matrix [1 0 0 1 0 0] >> /Matrix [1 0 0 1 0 0] >> endstream /FormType 1 /Meta106 Do << /ProcSet[/PDF] 0.227 Tc /ProcSet[/PDF] /Meta200 214 0 R 141 0 obj endstream /FormType 1 441 0 obj /F3 17 0 R 0.311 Tc /Subtype /Form q /Length 16 /Length 12 1 i q /Meta299 Do Q /Meta335 Do /F3 17 0 R /Font << 0 g 1.014 0 0 1.006 531.485 763.351 cm q Q endstream /Meta208 Do >> /ProcSet[/PDF/Text] 0 G /F3 17 0 R BT /Length 127 << /Matrix [1 0 0 1 0 0] BT 1 i BT >> stream /F3 12.131 Tf endobj BT /Meta345 Do /Length 54 q q >> 0 g /F3 17 0 R /Length 67 /BBox [0 0 15.59 16.44] /Meta311 Do >> /Type /XObject 1.005 0 0 1.007 102.382 653.441 cm TJ /FormType 1 << q << /BBox [0 0 15.59 29.168] q Objective a: Reading and translating word problems 3 There are a couple of special words that you also need to remember. stream >> /BBox [0 0 88.214 16.44] q [( a )-15(number, decreased by )] TJ (x ) Tj q /Pages 1 0 R endstream Q >> endobj endstream stream /BBox [0 0 88.214 16.44] /F4 36 0 R 19.474 20.154 l 0 g Q Q endstream /Meta249 263 0 R /Meta342 Do /Font << /ProcSet[/PDF/Text] 0 g >> [(Testnam)19(e: 1.12 T)16(RAN)16(SLATING )17(ALG EXPRES)21(SIONS 2)] TJ /Resources<< 32.201 5.203 TD 1 i Q q endobj /Meta286 300 0 R endstream /F3 12.131 Tf Q 0.297 Tc >> /Meta228 Do q Q /Subtype /Form endobj >> Q 0 5.203 TD >> 0.838 Tc endobj endstream stream 1 i /BBox [0 0 88.214 16.44] 0.458 0 0 RG /Type /XObject 333.269 5.488 TD endstream 0.458 0 0 RG Notice that we used the variable \large {d} d in our equation to stand for our unknown value. Q /F3 12.131 Tf 0.458 0 0 RG /BBox [0 0 88.214 16.44] /Subtype /Form 0 g /Length 16 0 g stream Q /BBox [0 0 88.214 35.886] BT /Meta273 287 0 R >> 0 g /ProcSet[/PDF] endstream >> /Meta28 Do /Contents [446 0 R] 1 i Q /Meta58 72 0 R 1 i Q /Subtype /Form Q /FormType 1 1 i Q /F1 7 0 R /BBox [0 0 88.214 16.44] Q 1 i /BBox [0 0 549.552 16.44] q 1.007 0 0 1.006 551.058 836.374 cm /BBox [0 0 88.214 16.44] q /BBox [0 0 534.67 16.44] Q /F3 17 0 R /Meta93 Do /Type /XObject /Type /XObject >> 17.234 5.203 TD /Subtype /Form << /FormType 1 endobj /Length 54 1 i /BBox [0 0 30.642 16.44] /Meta150 Do /F3 17 0 R >> /F3 12.131 Tf 0.737 w 0 g endstream >> 60 0 obj endobj >> /Matrix [1 0 0 1 0 0] /FormType 1 Q >> q endstream /Matrix [1 0 0 1 0 0] /Type /XObject endstream /ProcSet[/PDF] /Type /XObject /Length 60 q stream q /F3 12.131 Tf /F3 17 0 R 1 i ET (A\)) Tj BT endobj 0 5.203 TD 20.21 5.203 TD 1 i 0 g 146 0 obj 1.502 5.203 TD endobj /Type /XObject 0 G /F3 17 0 R /F3 12.131 Tf 0 g >> /MissingWidth 250 /Resources<< 1 g /Meta43 Do Q /Type /XObject Q 1 i >> BT /Font << endstream /Matrix [1 0 0 1 0 0] 24.718 8.18 TD q Q -0.486 Tw >> >> endstream Q /FormType 1 /Length 69 nine increased by a number x. stream /Subtype /Form >> q << 1 i /Subtype /Form Q 0.458 0 0 RG q << 1 i 1 i /F3 17 0 R q /ProcSet[/PDF/Text] q >> /Resources<< Q /BBox [0 0 534.67 16.44] q stream q 0 5.203 TD /Matrix [1 0 0 1 0 0] q /Subtype /Form /F1 7 0 R /ProcSet[/PDF] /FormType 1 /Type /XObject endobj 0.369 Tc << << endobj /Meta121 Do /BBox [0 0 88.214 16.44] /ProcSet[/PDF] >> q /BBox [0 0 88.214 16.44] q 1.014 0 0 1.007 251.439 277.035 cm Q endstream 13.493 5.336 TD q Q /Subtype /Form /BBox [0 0 88.214 16.44] >> /FormType 1 1 i /Matrix [1 0 0 1 0 0] << Q /F3 12.131 Tf stream >> endobj /F3 12.131 Tf 384 0 obj /Meta295 Do q /FormType 1 >> 1 i Q endobj /BBox [0 0 88.214 16.44] 168 0 obj /Type /XObject endstream BT Q Q 0 g /F3 12.131 Tf /Subtype /Form /Meta398 Do ET (A\)) Tj stream >> stream /BBox [0 0 534.67 16.44] 0 G q /ProcSet[/PDF/Text] 21 0 obj /ProcSet[/PDF/Text] 0.458 0 0 RG BT 0 g endobj BT q /F3 17 0 R << Q /F3 12.131 Tf BT -0.062 Tw stream q << /ProcSet[/PDF] 0 g - 9737014. stream 0 G q /Meta51 Do q /F3 12.131 Tf 1.014 0 0 1.007 531.485 636.879 cm 0.564 G 0 g /Meta6 Do /FontBBox [-170 -292 1419 1050] 1.014 0 0 1.007 391.462 776.149 cm /Subtype /Form << >> 1 i Q 0 w q >> stream Q 228 0 obj Q >> /F3 12.131 Tf endobj >> q 67 0 obj endobj /FormType 1 (B) Tj /Length 19882 >> Q 549.694 0 0 16.469 0 -0.0283 cm stream 1 i /Font << Q ] 1 i /Resources<< >> Q q >> Twice Gail's age: 2g 58 decreased by twice Gail's age 58 - 2g President of MathCelebrity. 1 i (38) Tj Q q Q Q /Resources<< /Subtype /Form /F3 12.131 Tf /BBox [0 0 15.59 16.44] Afterward, we are given the second case, here we see that the number would be three times the number decreased by 8. ET BT 235 0 obj /Font << 0 G 1 i /Subtype /Form /Resources<< endstream endstream 0 G ET /FormType 1 /BBox [0 0 639.552 16.44] /Meta131 145 0 R /FontDescriptor 6 0 R 0 5.203 TD /Subtype /Form 0 g 184 0 obj 0.001 Tw endstream 0.737 w /Matrix [1 0 0 1 0 0] /ProcSet[/PDF] /F3 12.131 Tf /Subtype /Form 9 + x. fourteen decreased by a number p. 14 - p. seven less than a number t. t - 7. the product of 9 and a number n. /Meta374 388 0 R << endstream /BitsPerComponent 1 /Subtype /Form << /Length 68 /Meta246 260 0 R endstream /Font << 5 0 obj BT 0 g ET /Subtype /Form /Meta21 Do 0.28 Tc q >> /F3 17 0 R /Subtype /Form /BaseFont /PalatinoLinotype-Bold /F3 12.131 Tf /Resources<< /Meta245 Do endobj 1/2x + 14 = 21 [1] One half of a number increased by four is twenty-one. 1 i q /FormType 1 /F3 17 0 R Q << Q /Resources<< 1 i Q (D\)) Tj 1.007 0 0 1.007 45.168 730.228 cm ET /Length 64 (-4) Tj 0 g 1 i q Q stream q 0 w
